MCQ
Milli equivalent of :-
$(a)\, Ca(OH)_2$ in $74 \,gm$
$(a)\, Ca(OH)_2$ in $74 \,gm$
$(b)\, NaOH$ in $20\, gm$ will be respectively.
- ✓$2000, 500$
- B$500, 2000$
- C$50, 200$
- D$200, 50$
$(b)\, NaOH$ in $20\, gm$ will be respectively.
$=\frac{74}{74 / 2} \times 1000=2000$
$\left(\because E_{\mathrm{Ca}(\mathrm{OH})_{2}}=\frac{74}{2}^{-}\right)$
(b) Meq. of $\mathrm{NaOH}=\frac{20}{40} \times 1000=500$
$\left(\because E_{\mathrm{NaOH}}=40\right)$
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Assertion $(A)$: Cis form of alkene is found to be more polar than the trans form
Reason $(R)$: Dipole moment of trans isomer of $2$-butene is zero.
In the light of the above statements, choose the correct answer from the options given below :