MCQ
Minimum excitation potential of Bohr's first orbit in hydrogen atom is
- A$13.6 V$
- B$3.4 V$
- ✓$10.2 V$
- D$3.6 V$
✓
Answer
Correct option: C.
$10.2 V$
$\text { Excitation potential }=\frac{\text { Excitationenergy }}{\mathrm{e}}$
Minimum excitation energy corresponds to excitation from $n=1$ to $n=2$
$\therefore$ Minimum excitation energy in hydrogen atom $=-3.4-(-13.6)=+10.2 \mathrm{eV}$
so minimum excitation potential $=10.2 \mathrm{eV}$.
Minimum excitation energy corresponds to excitation from $n=1$ to $n=2$
$\therefore$ Minimum excitation energy in hydrogen atom $=-3.4-(-13.6)=+10.2 \mathrm{eV}$
so minimum excitation potential $=10.2 \mathrm{eV}$.
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