Mode =? - Vidyadip

MCQ

Mode $=?$

A
$\text{x}_\text{k}+\text{h}.\Big\{\frac{(\text{f}_{\text{k}-1}-\text{f}_\text{k})}{(2\text{f}_\text{k}-\text{f}_{\text{k}-1}-\text{f}_{\text{k}+1})}\Big\}$
✓
$\text{x}_\text{k}+\text{h}.\Big\{\frac{(\text{f}_\text{k}-\text{f}_{\text{k}-1})}{(2\text{f}_\text{k}-\text{f}_{\text{k}-1}-\text{f}_{\text{k}+1})}\Big\}$
C
$\text{x}_\text{k}+\text{h}.\Big\{\frac{(\text{f}_\text{k}-\text{f}_{\text{k}-1})}{(\text{f}_\text{k}-2\text{f}_{\text{k}-1}-\text{f}_{\text{k}-1})}\Big\}$
D
$\text{x}_\text{k}+\text{h}.\Big\{\frac{(\text{f}_\text{k}-\text{f}_{\text{k}-1})}{(\text{f}_{\text{k}}-\text{f}_{\text{k}-1}-2\text{f}_{\text{k}+1})}\Big\}$

✓

Answer

Correct option: B.

$\text{x}_\text{k}+\text{h}.\Big\{\frac{(\text{f}_\text{k}-\text{f}_{\text{k}-1})}{(2\text{f}_\text{k}-\text{f}_{\text{k}-1}-\text{f}_{\text{k}+1})}\Big\}$

$\text{x}_\text{k}+\text{h}.\Big\{\frac{(\text{f}_\text{k}-\text{f}_{\text{k}-1})}{(2\text{f}_\text{k}-\text{f}_{\text{k}-1}-\text{f}_{\text{k}+1})}\Big\}$

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