$N _{2}$ gas is heated from $300\, K$ temperature to $600\, K$ through an isobaric process. Then find the change in entropy of the gas. $( n =1 mole )$ (in $J/K$)
AIIMS 2019, Diffcult
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The change of entropy for an isobaric process is given by,
$\Delta S=n C_{P} \int_{I_{1}}^{T_{2}} \frac{d T}{T}$
$=n C_{P} \ln \left(\frac{T_{2}}{T_{1}}\right)$
Substitute 1for $n, \frac{7}{2} R$ for $C_{p}, 600$ for $T_{2}$ and 300 for $T_{1}$ in above relation,
$\Delta S=1 \times \frac{7}{2} R \ln \left(\frac{600}{300}\right)$
$\approx 20 J / K$
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