$(152\;sc{m^2}) \wedge _{KBr}^0\; = \; \wedge _{{K^ + }}^0 + \wedge _{B{r^ - }}^0$ ..... $(2)$
$(150\;sc{m^2}) \wedge _{KCl}^0\; = \; \wedge _{{K^ + }}^0 + \wedge _{C{l^ - }}^0$ ..... $(3)$
By equation $(1)+(2) \,-\,(3)$
$ \wedge _{NaBr}^0\; = \; \wedge _{N{a^ + }}^0 + \wedge _{B{r^ - }}^0$
$= 126 + 152 - 150 = 128$ $Scm^2 mol^{-1}$
$Mn^{2+} + 2e^- \rightarrow Mn,\, $$E^o = - 1.18\, V$
$Mn^{2+} \rightarrow Mn^{3+} + e^-,$ $ E^o = - 1.51 \,V$
તો પ્રક્યિા $3Mn^{2+} \rightarrow Mn^o + 2Mn^{3+},$ માટે $E^o$ તથા પુરોગામી પ્રક્રિયાની શક્યતા અનુક્રમે .... થશે.
$E^oFe^{3+}_{(aq)} + e^{-} \rightarrow Fe^{2+}_{(aq)}$ કેટલા ............ $\mathrm{V}$ થાય?
$Fe^{3+}\,\,_{(aq)} + 3e^{-} \rightarrow Fe_{(s)}$ ; $E^o = -0.036 \,volt; $
$Fe^{2+}_{(aq)} + 2e^{-} \rightarrow Fe_{(s)}$ ; $E^o = -0.440 \,volt$
$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$