$(1)$ $\lambda_{ m }^{\infty}( NaI )=12.7 \,m\,S m ^{2}\, mol ^{-1}$
$(2)$ $\lambda_{ m }^{\infty}\left( NaNO _{3}\right)=12.0 \,m\,S m ^{2}\, mol ^{-1}$
$(3)$ $\lambda_{ m }^{\infty}\left( AgNO _{3}\right)=13.3\,m\,S m ^{2}\, mol ^{-1}$
$\lambda_{ m }^{\infty}( Ag I )=(1)+(3)-(2)$
$=12.7+13.3-12.0$
$=26.0-12.0$
$\lambda_{ m }^{\infty}( Ag I )=14.0$
(નજીકનાં પૂર્ણાંકમાં રાઉન્ડ ઑફ). $\left[\right.$ આપેલ $, E_{C u^{2+} / C u}^{o}=0.34\, V , E _{ NO _{3}^{-} / NO_2 }^{\circ}=0.96\, V$ $,E _{ NO _{3} / NO _{2}}^{\circ}=0.79 \,V$ $\left.\frac{ RT }{ F }(2.303)=0.059\right]$
$Cu(s) + 2Ag{^+}_{(aq)} \to Cu^{+2}_{(aq)} + 2Ag(s)$
માટે સંતુલન અચળાંક $K_C = 10 \times 10^{15}$ છે, તો $298\, K$ ને $E_{cell}^o$ નું મૂલ્ય કેટલુ થશે?
[${2.303\,\frac{{RT}}{F}}$ એ $298\,K$ $=0.059\,V$]
${Cu}({s})\left|{Cu}^{2+}({aq})(0.01 {M}) \| {Ag}^{+}({aq})(0.001 {M})\right| {Ag}({s})$ કોષ માટે ,કોષનો પોટેન્શિયલ $=.....\times 10^{-2} {~V}$
[ઉપયોગ : $\frac{2.303 {RT}}{{F}}=0.059$ ]