$A.$ $n =3, l =0, m =0$
$B.$ $n =4, l =0, m =0$
$C.$ $n =3, l =1, m =0$
$D.$ $n =3, l =2, m =1$
ક્રમ માટે સાયો વિકલ્પ શોધો :
\((B)\) \(n =4 ; 1=0 ; m =0 ; 4 s\) orbital
\((C)\) \(n =3 ; 1=1 ; m =0 ; 3 p\) orbital
\((D)\) \(n =3 ; 1=2 ; m =0 ; 3 d\) orbital
As per Hund's rule energy is given by \(( n +l)\) value.
If value of \(( n +l)\) remains same then energy is given by \(n\) only.