$n - Bu -\equiv\frac{(i) n-BuLi,n - C _{5} H _{11} Cl}{(ii) Lindlar\,\, cat, H _{2}}$
$n - C _{5} H _{11} Cl \downarrow$ (SN reaction)
${\left( {C{H_3}} \right)_3}C - CH = C{H_2}\xrightarrow[{\left( {ii} \right)\,NaB{H_4} + NaOH}]{{\left( i \right)\,Hg{{\left( {C{H_3}COO} \right)}_2};\,THF}}\,?$

