વિધાન $I$: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ અને $\left[\mathrm{CoF}_6\right]^{3-}$ બંને સંકીણો અષ્ટફ્લકીય છે, પણ તેમની ચુંબકીય વર્તણૂક જુદી છે,
વિધાન $II$: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ એ પ્રતિસુંબકીય છે, જ્યારે $\left[\mathrm{CoF}_6\right]^{3-}$ એ અનુસુંબકીય છે.
ઉપરનાં વિધાનોના સંદર્ભમાં નીચે આપેલા વિક્લ્પોમાંથી સાચો જવાબ પસંદ કરો.
Electronic configuration of \(\mathrm{Co}^{3+}\) \(Image\)
In presence of \(\mathrm{NH}_3\) ligand, pairing of electrons takes place and it becomes diamagnetic complex ion.
In presence of \(\mathrm{NH}_3\) ligand \(Image\)
\(\therefore \quad\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\) is octahedral with \(\mathrm{d}^2 \mathrm{sp}^3\) hybridisation and it is diamagnetic in nature.
In case of \(\left[\mathrm{CoF}_6\right]^{3-}, \mathrm{Co}\) is in +3 oxidation state and it is having \(3 \mathrm{~d}^6\) configuration.
In presence of weak field \(\mathrm{F}^{-}\)ligand, pairing does not take place.
In presence of \(\mathrm{F}^{-}\)ligands \(Image\)
\(\therefore \quad \operatorname{In}\left[\mathrm{CoF}_6\right]^{3-}, \mathrm{Co}^{3+}\) is \(\mathrm{sp}^3 \mathrm{~d}^2\) hybridised with four unpaired electrons, so it is paramagnetic in nature.
| સૂચિ $- I$ | સૂચિ $- II$ |
| $(a)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ | $(i)$ $5.92 \,\mathrm{BM}$ |
| $(b)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ | $(ii)$ $0 \,\mathrm{BM}$ |
| $(c)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$ | $(iii)$ $4.90\, \mathrm{BM}$ |
| $(d)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ | $(iv)$ $1.73\, \mathrm{BM}$ |
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
