d (d) Dissociation of proton from $C{H_3} - \mathop N\limits^ + {H_3}C{l^ - }$ is very difficult due to $-I$ effect of $C{l^ - }$ and ${N^ + }$ while in ${C_6}{H_5}OH$ due to resonance stabilization of phenoxide ion proton eliminate easily similarly due to $H-$ bonding in ${C_6}{H_5}C{H_2}OH$ it can be eliminate and $C{H_3}C \equiv CH$ show acidic character by triple bond by which proton can be dissociate.
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