\((b)\) In \({(N{H_4})_2}[TiC{l_6}]\,Ti\) is in \(+4\) oxidation state, hence has no unpaired electron hence colourless and diamagnetic.
\((c)\) In \(VOSO_4\), is in \(+4\) oxidation state, hence has no unpaired electron ,thus it is coloured and paramagnetic.
\((a)\) In \(K_2Cr_2O_7\) \(Cr\) is in \(+6\) oxidation state, hence has no unpaired electron and thus it is diamagnetic. Though \(K_2Cr_2O_7\) has no unpaired electron but it is coloured. this is due to charge transfer.
સૂચિ $I$ (Complexes) | સૂચિ $II$ (Hybridisation) |
$A$ $\left[ Ni ( CO )_4\right]$ | $I$ $sp ^3$ |
$B$ $\left[ Cu \left( NH _3\right)_4\right]^{2+}$ | $II$ $dsp^2$ |
$C$ $\left[ Fe \left( NH _3\right)_6\right]^{2+}$ | $III$ $sp^3d^2$ |
$D$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ | $IV$ $d^2sp^3$ |
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