${[\mathop {Fe}\limits^{III} {(N{H_3})_6}]^{3 + }}:{\mkern 1mu} Hyb.{\mkern 1mu} :{\mkern 1mu} {d^2}s{p^3},{\mu _{eff}} = \sqrt 3 {\mkern 1mu} B.M.$
$[Co{{(CO)}_{4}}]:\,Hyb.\,:\,ds{{p}^{2}},{{\mu }_{eff}}=\sqrt{3}\,B.M.$
${{[Cu{{({{H}_{2}}O)}_{6}}]}^{2+}}:\,Hyb.\,:\,s{{p}^{3}}{{d}^{2}},{{\mu }_{eff}}=\sqrt{3}\,B.M.$