Since, all the' electrons are paired, it is a diamagnetic specie. \(\mathrm{N}_{2}(7+7=14)=\sigma 1 \mathrm{s}^{2},{ }^{\star} \mathrm{\sigma} \cdot 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}\)

\(\stackrel{*}{\sigma} 2 s^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \sigma 2 p_{z}^{2}\)

It is also a diamagnetic specie because of the absence of unpaired electrons.

\(0_{2}(8+8=16)\)

\(\mathrm{Or} \quad \mathrm{S}_{2}=\sigma 1 \mathrm{s}^{2}, \stackrel{*}{\sigma} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2},{ }^{*} 2 \mathrm{s}^{2}\)

\(\sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi 2 p_{x}^{1} \approx \pi 2 p_{y}^{1}\)

Since, \(\mathrm{O}_{2}\) or \(\mathrm{S}_{2}\) contain 2 unpaired electrons, therefore they are paramagnetic.