નીચેના સંકીણમાં ફક્ત સ્પીન આધારિત ચુંબકીય ચાકમાત્રાને સાચો ક્રમ જણાવો

$(I)$ $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Br}_{2}$

$(II)$ $ \mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$

$(III)$ $\mathrm{Na}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\left(\Delta_{0}>\mathrm{P}\right)$

$(IV)$ $\left(\mathrm{Et}_{4} \mathrm{N}\right)_{2}\left[\mathrm{CoCl}_{4}\right]$

Question

નીચેના સંકીણમાં ફક્ત સ્પીન આધારિત ચુંબકીય ચાકમાત્રાને સાચો ક્રમ જણાવો

$(I)$ $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Br}_{2}$

$(II)$ $ \mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$

$(III)$ $\mathrm{Na}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\left(\Delta_{0}>\mathrm{P}\right)$

$(IV)$ $\left(\mathrm{Et}_{4} \mathrm{N}\right)_{2}\left[\mathrm{CoCl}_{4}\right]$

JEE MAIN 2020, Diffcult

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Solution

b
$(I)\;\;\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$

$\mathrm{Cr}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{d}^{4}$

$\mathrm{H}_{2} \mathrm{O} \rightarrow$ Weak field ligand

$\text { Unpaired } \mathrm{e}^{-}=4$

$\text { Magnetic moment } =\sqrt{24} \mathrm{BM} =4.89 \mathrm{BM}$

$(II)\;\;\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$

$\mathrm{Fe}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{d}^{6}$

$\mathrm{CN}^{-} \rightarrow$ Strong field ligand

Unpaired $\mathrm{e}^{-}=0$

Magnetic moment $=0 \mathrm{BM}$ $=0 \mathrm{BM}$

$\mathrm{III}\;\;\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$

$\mathrm{Fe}^{+3} \Rightarrow[\mathrm{Ar}] 3 \mathrm{d}^{5}$

As $\Delta_{0}>P$

Unpaired $\mathrm{e}^{-}=1$

$\text { Magnetic moment } =\sqrt{3} \mathrm{BM}$$=1.73 \mathrm{BM}$

$(IV)\;\;\left(\mathrm{Et}_{4} \mathrm{N}\right)^{+}\left[\mathrm{CoCl}_{4}\right]^{2-}$

$\mathrm{Co}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{d}^{7}$

Unpaired electrons $=3$

$\begin{aligned} \text { Magnetic moment } &=\sqrt{15} \mathrm{BM} \\ &=3.87 \mathrm{BM} \end{aligned}$

Hence order of magnetic moment is $I>IV>III>II$

સૂચી $-I$	સૂચી $-II$
$A.$ $\mathrm{K}_2\left[\mathrm{Ni}(\mathrm{CN})_4\right]$	$I$ $\mathrm{sp}^3$
$B.$ $\left[\mathrm{Ni}(\mathrm{CO})_4\right]$	$II$ $\mathrm{sp}^3 \mathrm{~d}^2$
$C.$ $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3$	$III$ $\mathrm{dsp}^2$
$D.$ $\mathrm{Na}_3\left[\mathrm{CoF}_6\right]$	$IV$ $\mathrm{d}^2 \mathrm{sp}^3$

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