a $(a)\, NO^+\, =7+8-1\,=14\,e^-$. $O_2\, = 16\,e^-$. i.e. not isoelectronic $(b)$ Boron forms only covalent compounds. This is due to its extremely high ionisation energy. $(c)$ Compounds of $Ti^+$ are much more stable than those of $Ti^{3+}$. $(d)\, LiAlH_4$ is a versatile reducing agent in organic synthesis
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