$\mathop {{C_2}{H_5}OH}\limits_{\left( I \right)} $ $\mathop {{C_2}{H_5}Cl}\limits_{\left( {II} \right)} $ $\mathop {{C_2}{H_5}C{H_3}}\limits_{\left( {III} \right)} $ $\mathop {{C_2}{H_5}OC{H_3}}\limits_{\left( {IV} \right)} $
$[Figure]$ $\xrightarrow[{(ii)\,{H_2}S{O_4}\,,\,heat}]{{(i)\,OHCC{H_2}COCl}}$
$I. \,\,C{H_2} = CHC{H_2}Cl$
$II.\,\,C{H_3}C{H_2}C{H_2}Br$
$III.\,\,{(C{H_3})_3}CC{H_2}Br$
$IV.\,\,C{H_3}C{H_2}C{H_2}Cl$
$C{H_3}C{H_2}C{H_2}OH\,\xrightarrow{{PC{l_5}}}\,A\,\xrightarrow{{alc.\,\,KOH}}\,B$
નીપજ $'P'$ ધન સિરિક એમોનિયમ નાઇટ્રેટ કસોટી આપે છે આ આમાંથી કયા $ -OH $ જૂથ ની હાજરીને કારણે છે
${C_6}{H_5}C{H_2}CH(OH)CH{(C{H_3})_2}\xrightarrow{{conc.\,{H_2}S{O_4}}}\,?$