c
Among the substituents attached to the given compounds, fluorine has maximum electronegativity. So it will push electron pair towards it self. In option \((b),\)  the two \(F\) groups are attached opposite to each other thus net dipole moment will cancel each other and reduce its polarity. In option \((d),\)  the \(F\) groups are attached in slightly opposite direction thus this also decreases its polarity. But in option \((c),\)  the compound has the two \(F\)  groups along same direction. Thus net dipole moment will increase in this direction thus it will have maximum polarity. Thus the compound in option \((c)\)  has maximum polarity