$\frac{1}{2}C{l_2}(g)\xrightarrow{{\frac{1}{2}{\Delta _{diss}}{H^\Theta }}}Cl(g)\xrightarrow{{{\Delta _{eg}}{H^\Theta }}}$ $C{l^ - }(g)\xrightarrow{{{\Delta _{Hyd}}{H^\Theta }}}C{l^ - }(aq)$
તો $\frac{1}{2}C{l_2}(g)$ ના $Cl^-_{(aq)}$ માં રૂપાંતમાં ઊર્જાનો ફેરફાર ............. $\mathrm{kJ\,mol}^{-1}$ જણાવો.
$({{\Delta _{diss}}H_{C{l_2}}^\Theta } = 240\,kJ\,mol^{-1}, {{\Delta _{eg}}H_{C{l}}^\Theta }= -349 \,kJ\,mol^{-1},$${{\Delta _{Hyd}}H_{C{l}}^\Theta }= -381 \,kJ\,mol^{-1})$
$2 \mathrm{C}_{(\mathrm{s})}+2 \mathrm{O}_2(\mathrm{~g}) 2 \mathrm{CO}_2(\mathrm{~g}), \Delta \mathrm{H}=-787 \mathrm{KJ} ; \mathrm{H}_2(\mathrm{~g})+$$\mathrm{H}_2 \mathrm{O}, \Delta \mathrm{H}=-286 \mathrm{KJ}$
$\frac{1}{2} \mathrm{O}_2 \mathrm{C}_2 \mathrm{H}_2(g)+\frac{5}{2} \mathrm{O}_2(g) \rightarrow 2 \mathrm{CO}_2(g)+\mathrm{H}_2 \mathrm{O}(I), \Delta H=-1310KJ$