$C{H_2} = C{H_2}\xrightarrow{{{O_2}/Ag}}X\xrightarrow{{473\,{\kern 1pt} K}}Y$

$A\xrightarrow[{(ii)\,\,Conc.\,{H_2}S{O_4}/\Delta }]{{{\text{(i)}}\,{\text{C}}{{\text{H}}_3}MgBr/{H_2}O}}$

$B\xrightarrow[{(ii)\,Zn/{H_2}O}]{{(i)\,{O_3}}}C + D$

$D\xrightarrow[\Delta ]{{Ba\left( {OH} \right)}}\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {{H_3}C - C} \end{array}$$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,||} \\ { = CH - C - C{H_3}} \end{array}$

સૂચિ$-I$                                સૂચિ$-II$ 

$(I)$ બેન્ઝીન                         $( P )$ $HCl$ અને $SnCl _{2}, H _{3} O ^{+}$

$(II)$ બેન્ઝોનાઇટ્રાઇલ             $(Q)$ $H _{2}, Pd - BaSO _{4}, S$ અને ક્વિનોલાઇન

$(III)$ બેન્ઝોઇલ ક્લોરાઈડ       $(R)$ $CO , HCl$ અને $AlCl _{3}$