MCQ
Number of equivalents of $H_2SO_4$ present in $100\, mL$ of its solution. Whose $pH$ is $5$.
- A$10^{-4}$
- B$10^{-6}$
- C$10^{-2}$
- D$10^{-5}$
✓
Answer
$\mathrm{PH}=5 \Rightarrow\left[\mathrm{H}^{+}\right]=10^{-5} \mathrm{N}=\mathrm{N}_{\mathrm{H}_{2} \mathrm{SO}_{4}}$
Eq. of $\mathrm{H}_{2} \mathrm{SO}_{4}=10^{-5} \times 0.1=10^{-6}$ equivalents
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