A solution of 500 ,ml of 0.2 ,M ,KOH and 500 ,ml of 0.2 ,M ,HCl i… - Vidyadip

MCQ

A solution of $500\,ml$ of $0.2\,M\,KOH$ and $500\,ml$ of $0.2\,M\,HCl$ is mixed and stirred; the rise in temperature is ${T_1}$. The experiment is repeated using $250\,ml$ each of solution, the temperature raised is ${T_2}$. Which of the following is true

✓
${T_1} = {T_2}$
B
${T_1} = 2{T_2}$
C
${T_1} = 4{T_2}$
D
${T_2} = 9{T_1}$

✓

Answer

Correct option: A.

${T_1} = {T_2}$

(a)Suppose heat evolved in Ist case is ${Q_1}$ and that in the IInd case it is ${Q_2}$. Then ${Q_2} = \frac{1}{2}{Q_{1.}}$
But ${Q_1} = 1000\,{T_1}$ and ${Q_2} = 500\,{T_2}$
$\therefore 500\,\,{T_2} = \frac{1}{2} \times 1000\,\,{T_1}\,\,i.e.\,{T_2} = {T_1}$.

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