MCQ
Number of optical isomers of lactic acid are
- A$1$
- ✓$2$
- C$3$
- D$4$
Only one chiral centre. Hence two optical isomers are possible.
No. of optical isomer = ${2^n}$ (where n = no. of chiral carbon) = ${2^1}$ $= 2.$
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$(a)$ $O_2^ - ,{O_2}$ $(b)$ ${N_2},N_2^ +$ $(c)$ $NO^+, NO^-$
$(C-H= 414; H-O = 463; H-Cl=431;$$ C-Cl=326, C-O=335)$
$CH_3-OH(g) + HCl(g) \rightarrow CH_3-Cl(g) + H_2O(g)$
$\underset{(1)}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,$
$\underset{(2)}{\mathop{\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$
$\underset{(3)}{\mathop{C{{H}_{3}}-CH=CH-OH}}\,$