\(\Rightarrow \frac{\ell n 2}{\lambda_{x}}=\frac{1}{\lambda_{y}} \Rightarrow \lambda_{x}=0.693 \lambda_{y}\)

Also initially \({N}_{{x}}={N}_{{y}}={N}_{0}\)

Activity \({A}=\lambda {N}\)

As \(\lambda_{{x}}<\lambda_{{y}} \Rightarrow {A}_{{x}}<{A}_{{y}}\)

\(\Rightarrow {y}\) will decay faster than \({x}\)