On a rough horizontal surface, a body of mass $2 \,kg$ is given a velocity of $10 \,m/s$. If the coefficient of friction is $0.2$ and $g = 10\, m/{s^2}$, the body will stop after covering a distance of ........ $m$
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(b)$S = \frac{{{u^2}}}{{2\mu g}} = \frac{{{{(10)}^2}}}{{2 \times 0.2 \times 10}} = 25\;m$
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