On each side of a polygon of $n$ sides a capacitor of capacitance $C$ is placed as shown in figure. Equivalent capacitance across $A$ and $B$ is
Medium
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$\mathrm{n}-1$ capacitance are in series combination.
$C_{1}=\frac{C}{n-1}$
$C_{e q}=\frac{C}{n-1}+C=\frac{C+(n-1) C}{n-1}=\frac{C n}{n-1}$
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