If $n$ drops, each of capacitance $C$, coalesce to form a single big drop, then the ratio of the energy stored in the big drop to that in each small drop will be
A$n : 1$
B$n^{1/3} : 1$
C$n^{5/3} : 1$
D$n^2 : 1$
Medium
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C$n^{5/3} : 1$
c (c) ${U_{Big}} = {n^{5/3}}\,{u_{small}}$
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