Download App

STD 12 - p -Block elements - ll — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - p -Block elements - ll4 Marks
MCQ
On heating ammonium dichromate and bariumazide separately we get 
  • ✓
    $N_2$ in both cases
  • B
    $N_2$ with ammonium dichromate and $NO$ with barium azide
  • C
    $N_2O$ with ammonium dichromate and $N_2$ with barium azide
  • D
    $N_2O$ with ammonium dichromate and $NO_2$ with barium azide
✓

Answer

Correct option: A.
$N_2$ in both cases
a
$\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow} \mathrm{N}_{2}+\mathrm{Cr}_{2} \mathrm{O}_{3}+4 \mathrm{H}_{2} \mathrm{O}$

$\mathrm{Ba}\left(\mathrm{N}_{3}\right)_{2} \rightarrow 3 \mathrm{N}_{2}+\mathrm{Ba}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

"The properties of the elements are periodic function of their atomic numbers." The  statement was given by :-
→
If a solution of $10^{-6}\, M\, HCl$ is diluted $100$ times, the $pH$ of solution is
→
Assertion : Dinegative anion of oxygen $(O^{2-})$ is quite common but dinegative anion of sulphur $(S^{2-})$ is less common.

Reason : Covalency of oxygen is two.

→
In the given reaction :

$NH_2-CH_2-CH_2-NH_2 +$ $\begin{array}{*{20}{c}}
  {COO{C_2}{H_5}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {COO{C_2}{H_5}} 
\end{array}$ $\xrightarrow{{Pyridne}}$ $[X]$

$[X]$ will be :

→
The values of heat of formation of $S{O_2}$ and $S{O_3}$ are $ - 298.2\,kJ$ and $ - 98.2\,kJ$. The heat of reaction of the following reaction will be.....$kJ$

$S{O_2} + \frac{1}{2}{O_2} \to S{O_3}$

→
$0.1\,g$ of metal combines with $46.6\,mL$ of oxygen at $STP.$ The equivalent weight of metal is.
→
Acetaldehyde can be converted into $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}OH} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {HO\, - \,C{H_2} - C - C{H_2}OH} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}OH} 
\end{array}$ by which reagent ?
→
A hard and resistant metal (alloy) generally used in tip of nib of fountain pen is
→
Maximum number of electrons in a subshell with $l = 3$ and $n = 4$ is
→
The solubility product of $1 \times {10^{ - 5}}$ is $1.44 \times {10^{ - 4}}$ at ${100\,^o}C$. The solubility of silver chloride in boiling water may be
→