One cannot see through fog because .......... :
- AFog absorbs light.
- BRefractive index of fog is unity.
- CLight suffers total internal reflection at the droplets in fog.
- DLight is scattered by the droplets in fog.
One cannot see through fog because .......... :
Explanation:
We cannot see through fog because of scattering.
Atoms and molecules in the air, including anything carried in the air like dust or smoke, will scatter light. Water droplets, as they are present in fog, also scatter light.
The light falling on an object and reflected to a viewer can be scattered to heck and back before it gets to the place where it can be 'seen' by an observer.
So the observer just sees a 'whiteout' instead of being able to make out anything beyond a few meters or so.
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Plane figures made of thin wires of resistance R = 50 milli ohm/metre are located in a uniform magnetic field perpendicular into the plane of the figures and which decrease at the rate dB/dt = 0.1 m T/s. Then currents in the inner and outer boundary are. (The inner radius a = 10 cm and outer radius b = 20 cm)

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(a) 10– 4 A (Clockwise), 2 × 10– 4 A (Clockwise) |
|
(b) 10– 4 A (Anticlockwise), 2 × 10– 4 A (Clockwise) |
|
(c) 2 × 10– 4 A (clockwise), 10– 4 A (Anticlockwise) |
|
(d) 2 × 10– 4 A (Anticlockwise), 10– 4 A (Anticlockwise) |
A charge q is placed at the centre of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is
|
(a) Zero |
(b) |
(c) |
(d) |



A moving coil galvanometer of resistance 100 is used as an ammeter using a resistance 0.1 The maximum deflection current in the galvanometer is 100A. Find the minimum current in the circuit so that the ammeter shows maximum deflection
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(a) 100.1 mA |
(b) 1000.1 mA |
(c) 10.01 mA |
(d) 1.01 mA |
Electromagnetic waves are transverse in nature is evident by
|
(a) Polarization |
(b) Interference |
(c) Reflection |
(d) Diffraction |