One end of a metal rod of length $1.0 m$ and area of cross section $100c{m^2}$ is maintained at ${100^o}C.$If the other end of the rod is maintained at ${0^o}C$, the quantity of heat transmitted through the rod per minute is (Coefficient of thermal conductivity of material of rod =$100W/m-K$)
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(b) $\frac{Q}{t} = \frac{{KA({\theta _1} - {\theta _2})}}{l} = \frac{{100 \times 100 \times {{10}^{ - 4}}(100 - 0)}}{1}$
$ \Rightarrow \frac{Q}{t} = 100\;Joule/\sec = 6 \times {10^3}\;Joule/\min $
$ \Rightarrow \frac{Q}{t} = 100\;Joule/\sec = 6 \times {10^3}\;Joule/\min $
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