Five identical rods are joined as shown in figure. Point $A$ and $C$ are maintained at temperature $120^o C$ and $20^o C$ respectively. The temperature of junction $B$ will be....... $^oC$
Medium
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(c) If thermal resistance of each rod is considered $R$ then, the given combination can be redrawn as follows
(Heat current)$_{AC} =$ (Heat current)$_{AB}$
$\frac{{(120 - 20)}}{R} = \frac{{(120 - \theta )}}{R}$
==> $\theta = 70^\circ C$
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