One end of a uniform rod of mass $m_1$ and crosssectional area $A$ is hung from a ceiling. The other end of the bar is supporting mass $m_2$. The stress at the midpoint is
Diffcult
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According to qestion.
Weight of suspended mass:
$W_1=m_1\,g$
only half of the weight of the rod acting at the mid point,
$W _2=\frac{ m _2 g }{2}$
strees at the mid point :
$\text { Stress } =\frac{ W _1+ W _2}{ A }$
$\Rightarrow \frac{ m _1 g +\frac{ m _2 g }{2}}{ A }$
$\Rightarrow \frac{\frac{2 m _1 g + m _2 g }{2}}{ A }$
$\therefore \frac{ g \left(2 m _1+ m _2\right)}{2 A }$
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