$\Delta \mathrm{U}=\mathrm{C}_{\mathrm{v}} \Delta \mathrm{T}$
(for $1$ mole of ideal gas)
and from Mayer's formula,
$\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}=\mathrm{R}$
$\frac{C_{p}}{C_{v}}-1=\frac{R}{C_{v}} \Rightarrow \gamma-1=\frac{R}{C_{v}}$ or $C_{v}=\frac{R}{\gamma-1}$
$\therefore \Delta \mathrm{U}=\frac{\mathrm{R} . \Delta \mathrm{T}}{\gamma-1}=\frac{8.3 \times(35-27)}{1.4-1}$
$=\frac{8.3 \times 8}{0.4}=166 \mathrm{J}$
Let $\Delta v=X$ cc and $\Delta p=Y \times 10^3 Pa$.
($1$) The value of $X$ is
($2$) The value of $Y$ is
Give the answer or quetion ($1$) and ($2$)
