One mole of an ideal gas is contained with in a cylinder by a frictionless piston and is initially at temperature $T$. The pressure of the gas is kept constant while it is heated and its volume doubles. If $R$ is molar gas constant, the work done by the gas in increasing its volume is
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Expression for work done is given by.
$W=P \Delta V$
Given that
$\mathrm{P}=$ Constant
And volume is doubled from initial position.
$W=P(2 V-V)$
$=P V$
But, by ldeal gas equation $P V=n R T$
For $1$ mole gas, $P V=R T$
$\Rightarrow W=R T$
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