One mole of an ideal monoatomic gas at temperature T_0 expands slowly according to the law P/V = constant. If the final temperature is 2

Q: One mole of an ideal monoatomic gas at temperature $T_0$ expands slowly according to the law $P/V$ = constant. If the final temperature is $2 \,\,T_0$, heat supplied to the gas is :

a In a process $P V^{x}=$ constant, molar heat capacity is given by $C=\frac{R}{\gamma+1}+\frac{R}{1-x}$ As the process is $\frac{P}{V}=$ constant i.e., $P V^{-1}=$ constant, therefore, $x=-1$ For an ideal monatomic gas, $\gamma=\frac{5}{3}$ $\therefore C=\frac{R}{\frac{5}{3}-1}+\frac{R}{1-(-1)}=\frac{3}{2} R+\frac{R}{2}=2 R$ $\Delta Q=n C(\Delta T)=1(2 R)\left(2 T_{0}-T_{0}\right)=2 R T_{0}$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

One mole of an ideal monoatomic gas at temperature $T_0$ expands slowly according to the law $P/V$ = constant. If the final temperature is $2 \,\,T_0$, heat supplied to the gas is :

A$2\,R\,{T_0}$
B$\frac{3}{2}\,R\,{T_0}$
C$\,R\,{T_0}$
D$\frac{1}{2}\,R\,{T_0}$

Medium

STD 11 Science
JEE
STD 11 - 12 . kinetic theory of gases
Physics

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