If $\mathrm{n}$ is the number density and $\mathrm{d}$ is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by :
A$\frac{1}{\sqrt{2 n \pi d^2}}$
B$\sqrt{2} \mathrm{n} \pi \mathrm{d}^2$
C$\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}$
D $\frac{1}{\sqrt{2} n^2 \pi^2 d^2}$
JEE MAIN 2024, Diffcult
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C$\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}$
c $\mathrm{n}=$ number of molecule per unit volume
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