MCQ
One mole of $NaCl$ $(s)$ on melting absorbed $30.5\,kJ$ of heat and its entropy is increased by $28.8\,J\,{K^{ - 1}}$. The melting point of $NaCl$ is ............. $\mathrm{K}$
- ✓$1059$
- B$30.5$
- C$28.8$
- D$28800$
Given that : $\Delta H = 30.5\,KJ\,mo{l^{ - 1}}$
$\Delta S = 28.8\,J{K^{ - 1}} = 28.8 \times {10^{ - 3}}\,KJ\,{K^{ - 1}}$
By using $\Delta S = \frac{{\Delta H}}{T}$
$ = \frac{{30.5}}{{28.8 \times {{10}^{ - 3}}}} = 1059\,K$
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The functional group present in $B$ and name of the reaction would be
$(a) ClO_4^-> ClO_3^-> ClO_2^-> ClO^-$ Stability order
$(b) Cl_2 > Br_2> F_2> I_2$ Bond energy
$(c) OF_2 < OH_2< OCl_2$ Bond angle
$(d) I^-> Br^-> Cl^-$ Reducing power