MCQ
$\operatorname{cosec} 18^{\circ}$ એ . . . સમીકરણનું બીજ છે.
- A$x^{2}+2 x-4=0$
- B$4 x^{2}+2 x-1=0$
- C$x^{2}-2 x+4=0$
- ✓$x^{2}-2 x-4=0$
Let $\operatorname{cosec} 18^{\circ}=\mathrm{x}=\sqrt{5}+1$
$\Rightarrow \mathrm{x}-1=\sqrt{5}$
Squaring both sides, we get
$x^{2}-2 x+1=5$
$\Rightarrow x^{2}-2 x-4=0$
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