MCQ
$|cos x| = cos x - 2 sin x$ નો ઉકેલ ......... .
- A$x = n\pi$
- B$x = n\pi + \frac{\pi}{4}$
- ✓$x = (2n + 1)\pi + \frac{\pi}{4}$
- D$x = n\pi + (-1)^n \frac{\pi}{4}(n \in I)$
અહિ, $|cos x| = cos x - 2 sin x$
$cos x \geq 0$ તો $cos x = cos x - 2 sin x$
$\Rightarrow 2 sin x = 0$
$\Rightarrow sin x = 0 \Rightarrow x = 2n \pi$ અને
$cos \leq 0$ તો $-cosx=cosx-2sinx$
$\Rightarrow 2 sin x = 2 cos x$
$\Rightarrow \frac{sin x}{cos x} = 1 \Rightarrow tan x = 1$
$\Rightarrow x = \frac{\pi}{4} \Rightarrow x = 2n\pi + \frac{\pi}{4}$
અહી, $x = (2n + 1) \pi + \frac{\pi}{4}$
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