MCQ
Order of stability of conjugate base of the given acid is
  • $ii > i > iii$
  • B
    $i > ii > iii$
  • C
    $iii > ii > i$
  • D
    $iii > i > ii$

Answer

Correct option: A.
$ii > i > iii$
a
Acidity of these compounds can be explained on the basis of stability of conjugate base. The conjugate base carbanion of compound $lll$ is most stable as the charge is in delocalization and form resonating structures.

Conjugate base of compound II is least stable as it destroys the aromaticity of the compound. The carbon in $C H \equiv C^{-}$ is $sp$ hybrid and being electron negative it can hold the charge.

Therefore the order of stability of conjugate base is $III > I > II$ and hence the order of acidic strength is $II > I > III$.

Stronger the acid lower the value of $p K_{a}$. The order of $p K_{a}$ is $III < I < II.$

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