MCQ
Oxidation state of $‘S’ $ in ${H_2}S{O_3}$
- A$+3$
- B$+6$
- ✓$+4$
- D$+2$
$ + 2 + x - 2 \times 3 = 0$; $x = 6 - 2 = + 4$.
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$CH _3\left( CH _2\right)_4 CH _3 \xrightarrow[HCl,\Delta]{Anhy.AlCl_3} X$