$(B)$ $\mathrm{SO}_2$ is reducing while $\mathrm{TeO}_2$ is an oxidising agent.
$(C)$ The reducing property increases from $\mathrm{H}_2 \mathrm{~S}$ to $\mathrm{H}_2$ Tedown the group.
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$\begin{array}{*{20}{c}}
{C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - COOH}
\end{array}\xrightarrow{\Delta }(A)\xrightarrow{{C{H_3} - C{H_2}N{H_2}/\Delta }}(B)$
$(B)$ will be :
Complete copolymerization of 500 moles of $Q$ and $500$ moles of $R$ gives one mole of a single acyclic copolymer $U$.
[Given, atomic mass: $H=1, C=12, O=16$ ]
($1$) Sum of number of oxygen atoms in $S$ and $T$ is. . . . . .
($2$) The molecular weight of $U$ is
Give the answer or quetion $(1)$ and $(2)$