$P$ in $PO_4^{3-}$ માં $P$ નો, $SO_4^{2-}$ માં $S$ નો અને $Cr_2O_7^{2-}$ માં $Cr$ નો ઓક્સિડેશન આંક અનુક્રમે ..... થશે.

Question

AIPMT 2009, Medium

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Solution

d
(i) Sum of oxidation states of all atoms $=$ charge of ion.

(ii) oxidation number of oxygen $=-2$

Let the oxidation state of $\mathrm{P}$ in $\mathrm{PO}_{4}^{3-}$ " is $\mathrm{x}$. $\mathrm{PO}_{4}^{3-}$

$x+4(-2)=-3$

$x-8=-3$

$x=+5$

Let the oxidation state of $\mathrm{s}$ in $\mathrm{SO}_{4}^{2-}$ is $\mathrm{y}$

$y+4(-2)=-2$

$y-8=-2$

$y=+6$

Let the oxidation state of $\mathrm{Cr}$ in $\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}$ is $\mathrm{z}$

$2 \times z+7(-2)=-2$

$2 z-14=-2$

$z=+6$

Hence, oxidation state of $\mathrm{P}, \mathrm{S}$ and $\mathrm{Cr}$ are $+5,+6$ and $+6$

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