Question
P is a point on side BC of a $\triangle\text{ABC}$ such that AP bisects $\angle\text{BAC}.$ Then,
✓
Answer
- BA > BP
Solution:
Since, AP bisects $\angle\text{BAC}.$
Hence the point P on BC also bisects it as it the opposite side of $\angle\text{BAC}.$
Hence, we can conclude that, BA > BP.
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