MCQ
$Pascal-Second$ has dimension of
  • A
    Force
  • B
    Energy
  • C
    Pressure
  • Coefficient of viscosity

Answer

Correct option: D.
Coefficient of viscosity
d
Pascal is unit of pressure, hence its dimensional formula is

$\left[M L^{-1} T^{-2}\right]$

$\therefore$ Dimensional formula of Pascal-second is $\left[M L^{-1} T^{-1}\right]$

By the formula of coefficient of viscosity, we have

$\eta=\frac{F}{A(\Delta v / \Delta z)}$

where $F$ is force, $A$ is area and $\frac{\Delta v}{\Delta z}$ is velocity gradient.

$\therefore$ Dimensions of $\eta=\frac{\left[M L T^{-2}\right]}{\left[L^{2}\right]\left[L T^{-1} / L\right]}$

$=\left[M L^{-1} T^{-1}\right]$

Hence, Pascal-second has dimensions of coefficient of viscosity.

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