Potential difference between the points $P$ and $Q$ in the electric circuit shown is ................. $V$
Diffcult
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(d) Equivalent resistance between $P$ and $Q$
$\frac{1}{{{R_{PQ}}}} = \frac{1}{{(6 + 2)}} + \frac{1}{3} + \frac{1}{{(4 + 12)}}$
$==>$ ${R_{PQ}} = \frac{{48}}{{25}}\,\Omega $
Current between $P$ and $Q$; $i = 1.5\,A$
So, potential difference between $P$ and $Q$
${V_{PQ}} = 1.5 \times \frac{{48}}{{25}} = 2.88\,V$.
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