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Potential difference $(\triangle\text{V})$ between two points A and B separated by a distance x, in a uniform electric field E is given by $\triangle\text{V}=-\text{Ex},$ where xis measured parallel to the field lines. If a charge $q_0$ moves from P to Q, the change in potential energy $(\triangle\text{U})$ is given as $\triangle\text{U}=-\text{q}_0\triangle\text{V}.$ A proton is released from rest in uniform electric field of magnitude $4.0 \times 10^8Vm^{-1}$ directed along the positive X-axis. The proton undergoes a displacement of 0.25m in the direction of E. Mass of a proton $= 1.66 \times 10^{-27}kg$ and charge of proton $= 1.6 \times 10^{-19}C.$

1. The change in electric potential of the proton between the points A and B is:

1. $-1 \times 10^8V$
2. $1 \times 10^8V$
3. $6.4 \times 10^{-19}V$
4. $-6.4 \times 10^{-19}V$

2. The change in electric potential energy of the proton for displacement from A to B is:

1. $1.6 \times 10^{11}J$
2. $0.5 \times 10^{23}J$
3. $-1.6 \times 10^{-11}J$
4. $3.2 \times 10^{22}J$

3. The mutual electrostatic potential energy between two protons which are at a distance of $9 \times 10^{-15}$m, in $_{92}U^{235}$ nucleus is:

1. $1.56 \times 10^{-14}J$
2. $5.5 \times 10^{-14}J$
3. $2.56 \times 10^{-14}J$
4. $4.56 \times 10^{-14}J$

4. If a system consistsoftwocharges 4mC and -3mC with no external field placed at (-5cm, 0, 0) and (5cm, 0, 0) respectively. The amount of work required to separate the two charges infinitely away from each other is:

1. -1.1J
2. 2J
3. 2.5J
4. 3J

5. As the proton moves from P to Q, then:

1. The potential energy of proton decreases.
2. The potential energy of proton increases.
3. The proton loses kinetic energy.
4. Total energy of the proton increases.