Predict all the alkenes that would be formed by dehydrohalogenation of the following halides with sodium ethoxide in ethanol and identify the major alkene:
2,2,3-Trimethyl-3-bromopentane.
2,2,3-Trimethyl-3-bromopentane.
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In the 2, 2, 3-Trimethyl-3 bromopentane compounds, there are two different $\beta-\text{hydrogen}$ atoms. Thus, dehydrohalgenation of the compounds yields two alkenes.
Saytzeff’s rule implies that in dehydrohalgenation reaction, the alkene having a greater number of alkyl groups attached to a doubly bonded carbon atoms is perferably produced. Hence, alkene (I) is the major product in this reaction.
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