$\Delta {S^o} = - 1.00\,kJ\,{K^{ - 1}}$
From the equation
$\Delta G = \Delta {H^o} - T\Delta {S^o} = - 29.8 - (298 \times - 0.100)$
$ = - 29.8 + 29.8 = 0$
Now, $\Delta {G^o} = - 2.303\,RT\,\log \,{K_{eq}}$
$0 = - 2.303\,RT\,\log \,{K_{eq}}$
$\therefore {K_{eq}} = 1$
[ઉપયોગ : $\left.{R}=8.3 \,{~J} \,{~mol}^{-1}\, {~K}^{-1}\right]$
(ઉપયોગ કરો : $\Delta_{{c}} {H}($ ગ્લુકોઝ $)=-2700\, {~kJ}\, {~mol}^{-1}$ )