માં જો $OH^-$ ની સાંદ્રતા $1/4$ ગણી ઘટાડવામાં આવે તો $Fe^{3+}$ ની સંતુલન સાંદ્રતા .......... ગણી વધશે.
\(K=\frac{\left[F e^{3}+\right]\left[O H^{-}\right]^{3}}{\left[F e(O H)_{3}\right]} \ldots \ldots \ldots(i)\)
To maintain equilibrium constant, let the concentration of \(F e^{3+}\) is increased \(x\) times, on decreasing the concentration of \(O H^{-}\) by \(\frac{1}{4}\) times
\(K=\frac{\left[x F e^{3}\right]\left[\frac{1}{4} \times O hH\right]^{3}}{\left[F e\left(O H_{3}\right]\right.} \ldots \ldots \ldots(i i)\)
From Eqs. \((i)\) and \((ii)\)
\(\frac{1}{64} \times x=1\)
\(x=64 \)
(ઉપયોગ $R =8.31\, J\, K ^{-1}\, mol ^{-1} ; \log 2=0.3010$. In $10=$ $2.3, \log 3=0.477$ )