$3C{H_3}CH = C{H_2} + \frac{1}{2}{B_2}{H_6}\mathop {\xrightarrow{{{\text{Dry}}}}}\limits_{{\text{ether}}} {(C{H_3}C{H_2}C{H_3})_3}B$
${(C{H_3}C{H_2}C{H_3})_3}B\xrightarrow{{{H_2}{O_2}}}3C{H_3}C{H_2}C{H_2} - OH$
$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - C{H_2} - C{H_2} - OH}
\end{array}\,$ ${\xrightarrow[{Pyridine{\kern 1pt} cold}]{{Cr{O_3}}}}$ નીપજ